SUBNETTING CALCULATION

Subnetting calculation :

Here are the steps >>

STEP 1 :

Okay, so now we assumed that the IP Address is 192.168.0.0/16

IP Address : 192.168.0.0/16

Subnet Mask : 255.255.0.0

Class : C

Number of Subnet : 8

STEP 2:

In our case, the most minimum number of subnet which satisfies the requirement is 8. Thus, we will choose 8 as our subnet require. Where the condition should be:

2^n ; where n is the requirement

2^3 = 8 (this is a condition satisfied)

Hence, number of bits that will be borrowed will be equal to number of required subnet which is 3

STEP 3 :

128

64

32

16

8

4

2

1

128 + 64 + 32 = 224

we add all this three number because we borrow 3 bits

By refering above, hence the new Subnet Mask is 255.255.255.224

New prefix : /27

Class C
/24	255.255.255.0	254
/25	255.255.255.128	126
/26	255.255.255.192	62
/27	255.255.255.224	30
/28	255.255.255.240	14
/29	255.255.255.248	6
/30	255.255.255.252	2
/31	255.255.255.254	0
/32	255.255.255.255	0

 Based on this figure, the number of usable host is 30

STEP 4 : 

apply the subnet mask to the IP space

now, the network address 192.168.00 is subdivided into 8 subnets

As listed above in the table, these are the addresses which have been subdivided into 8 subnets with network IDs, usable host IDs and broadcast IDs. The IT Center is assigned in the 8th subnet which ranges from 192.168.0.224 - 192.168.0.255. In these range of addresses, the first address (192.168.0.224) is used as the network ID and the last address (192.168.0.255) is used as the broadcast ID. The Online Learning System is assigned as the 5th address in the 30 usable host ID's. Hence, the Online Learning System Server address is 192.168.0.158 /27.